2x^2+54x=180

Solution for 2x^2+54x=180 equation:

2x^2+54x=180

We move all terms to the left:

2x^2+54x-(180)=0

a = 2; b = 54; c = -180;
Δ = b2-4ac
Δ = 542-4·2·(-180)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-66}{2*2}=\frac{-120}{4}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+66}{2*2}=\frac{12}{4}
=3
$